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Patterns and further sequences

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CONTENTS

ITEM TYPE NUMBER
Investigating patterns and sequences Workout 52 slides
Patterns and sequences Library 13 questions
Once you have registered, you can work through the slides one by one. The workout comprises a series of sides that guide you systematically through the topic concept by concept, skill by skill. The slides may be used with or without the support of a tutor. The methodology is based on problem-solving that advances in logical succession by concept and difficulty. The student is presented with a problem or series of questions, and the next slide presents the fully-worked solution. To use the material you must sign-in or create an account. blacksacademy.net comprises a complete course in mathematics with resources that are comprehensive.

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SAMPLE FROM THE WORKOUT

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SLIDE 1 - QUESTION 1

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SLIDE 2 - SOLUTION

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SAMPLE FROM THE LIBRARY

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QUESTION [difficulty 0.1]

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SOLUTION

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DEPENDENCIES

286: Algebraic factors
288: Simultaneous equations
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298: Patterns and further sequences
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300: Algebraic manipulations

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CONCEPTS

ITEM
LEV.
Consolidation of finding formulas for patterns 700.1
Arithmetic progression / sequence 700.5
Common difference 700.5
nth term of an arithmetic sequence 700.9
Quadratic sequence 701.1
Difference of successive terms 701.3
Difference of differences 701.3
Difference of differences of a quadratic sequence 701.5
When difference of differences = 2a 701.7
Test for a quadratic sequence 701.9
Simultaneous problem from quadratic sequence 702.5
Ratio of successive terms of a sequence 702.7
Geometric progression / sequence 702.9
Constant ratio in a geometric sequence 702.9
Simultaneous problem from arithmetic sequence 703.1
Simultaneous problem from geometric sequence 703.3
Arithmetic sequence problem given a sum of terms 703.9
Geometric sequence problem given a sum of terms 704.1
Index problem in the context of a geometric sequence 704.7
Alternating sequence 704.9
Sequence generated by a rule 705.1

RAW CONTENT OF THE WORKOUT

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Algebraic manipulations SLIDE 1 The value of is how much more than the value of ? A 8 B 14 C D E SLIDE 2 The value of is how much more than the value of ? Solution B 14 SLIDE 3 If what is the value of ? A B 3 C D 19 E 192 SLIDE 4 If what is the value of ? Solution B 3 SLIDE 5 Which of the following is equivalent to ? A B C D E SLIDE 6 Solution E SLIDE 7 Which of the following expressions is equivalent to the one above? A B C D SLIDE 8 Solution A SLIDE 9 Example By expanding the left-hand side and equating coefficients, find a, b and c. Solution SLIDE 10 By equating coefficients, find a, b and c. SLIDE 11 SLIDE 12 The sum of and can be written in the form , where a, b and c are constants. What is the value of ? SLIDE 13 The sum of and can be written in the form , where a, b and c are constants. What is the value of ? Solution SLIDE 14 Given , find . SLIDE 15 SLIDE 16 ? Factorise ? Let and . By substituting into your answer to part ?, find . SLIDE 17 ? ? Given and and , then Note, SLIDE 18 The expression can be written in the form , where a and b are constants. Find . SLIDE 19 The expression can be written in the form , where a and b are constants. Find . Solution Hence SLIDE 20 Factorise ? ? ? Find without a calculator ? Find without a calculator SLIDE 21 Factorise ? ? ? ? SLIDE 22 Factorise ? ? ? ? SLIDE 23 ? ? ? ? SLIDE 24 Factorise ? ? ? ? ? SLIDE 25 ? ? ? ? ? Note. In the last by comparison with , which is the difference of two squares, where and . SLIDE 26 Singularity No function is defined where a denominator is equal to zero. For example, the function is undefined when , which is when . The reason for this is that in algebra it is never permitted to divide by zero. Any value where a function is undefined is called a singularity. SLIDE 27 State the values for which the following functions are undefined ? ? ? ? ? SLIDE 28 ? ? ? ? ? SLIDE 29 What is invalid (incorrect, wrong) about the following? What should be the correct solution to the equation? SLIDE 30 Strictly, we should write provided that . where is short for “x is not equal to 1”. Incorrect Correct We cannot have a solution because is undefined at . The correct and only answer is . SLIDE 31 Which of the following are all the solutions to the above? A B C D SLIDE 32 Solution C only SLIDE 33 ? Substitute and into , taking only the positive square root in each case. Consider the following ? Substitute into each line of the above, taking and state whether the line is true or false. ? Substitute into each line of the above, allowing and state whether the line is true or false. ? State the solutions of . SLIDE 34 ? Substituting and into and taking only the positive square root ? Substituting into each line ? Substituting into each line ? In fact, both and are solutions to because can be negative. SLIDE 35 Someone argues as follows On substituting into we obtain Hence, cannot be a solution to . Explain what is wrong with this argument and show that is a solution to SLIDE 36 The error in the argument is that . So, we have To show that is a solution to SLIDE 37 Which of the following is the solution set to ? A B C D E SLIDE 38 However, is not a solution to the original equation. Substitution of gives and . The reason why is not a solution is that in we cannot have a negative value under the root symbol. Thus . Hence the negative is not a solution. The answer is B, only. SLIDE 39 Simplify ? ? ? ? SLIDE 40 ? ? ? ? SLIDE 41 Factorize ? ? ? SLIDE 42 ? ? ? SLIDE 43 Find and simplify SLIDE 44 SLIDE 45 Find a, b and c for each of the following ? ? SLIDE 46 ? ? SLIDE 47 Find a, b and c for each of the following ? ? SLIDE 48 ? ? SLIDE 49 Example By substituting into solve Solution SLIDE 50 By substituting or otherwise solve ? ? SLIDE 51 ? ? SLIDE 52 If n is an integer, prove that the sum of and is a square number. SLIDE 53 If n is an integer, prove that the sum of and is a square number. Solution SLIDE 54 Let n be an integer. Prove that is the product of three consecutive number. SLIDE 55 SLIDE 56 Example Prove algebraically that Solution Let , then In general If is an infinitely recurring decimal expansion, then . If is an infinitely recurring decimal expansion, then . If is an infinitely recurring decimal expansion, then . Likewise, for any recurring decimal expansion. SLIDE 57 ? Find the fraction equivalent to , expressing this fraction in its lowest terms. ? Prove algebraically that is the fraction you found. SLIDE 58 ? ? To prove algebraically that Proof Let , then SLIDE 59 Prove algebraically that SLIDE 60 Prove algebraically that Solution SLIDE 61 A sphere has been cut into four equal quarters. The volume of each quarter is . Find the surface area of each quarter, giving your answer to 3 significant figures. SLIDE 62 A sphere has been cut into four equal quarters. The volume of each quarter is . Find the surface area of each quarter, giving your answer to 3 significant figures. Solution The surface is in three parts. The “outer” part is of the surface of the sphere, and the two “inner” parts are both semicircles passing through the centre of the sphere. SLIDE 61B A sphere has been cut into four equal quarters. The volume of each quarter is . Find the surface area of each quarter, giving your answer to 3 significant figures. SLIDE 62B A sphere has been cut into four equal quarters. The volume of each quarter is . Find the surface area of each quarter, giving your answer to 3 significant figures. Solution The surface is in three parts. The “outer” part is of the surface of the sphere, and the two “inner” parts are both semicircles passing through the centre of the sphere.