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Completing the square

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CONTENTS

ITEM TYPE NUMBER
Quadratics in canonical form Workout 54 slides
Completing the square Library 17 questions
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SAMPLE FROM THE WORKOUT

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SLIDE 1 - QUESTION 1

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SLIDE 2 - EXPLANATION

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SAMPLE FROM THE LIBRARY

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QUESTION [difficulty 0.2]

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SOLUTION

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DEPENDENCIES

318: Algebraic products
320: Finding roots
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326: Completing the square
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334: Transformations of curves
340: Quadratic inequalities
346: Circles, curves and lines
763:  Introduction to the differential calculus

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CONCEPTS

ITEM
LEV.
Consolidation of the quadratic formula 784.1
The form μ(x - α)^2 + β 784.5
min / max at (α, β), axis of symmetry at x = α 784.7
The completed square 784.9
Canonical or standard form 784.9
Algebraic method for finding the completed square 785.0
Where μ < 0 785.2
Completing the square by direct manipulation 785.4
Plus/minus trick 785.4
Extending direct manipulation to fractions 786.1
Quadratic that does not have roots 786.7
Real roots 786.9
Square root of a negative number 787.0
Where x^2 coefficient is not unitary 787.5
Effect of μ on the parabola 787.8
Effect of μ < 0 on the parabola 788.2
Proof of the quadratic formula 788.4
Roots of a quadratic from the completed square 789.3

RAW CONTENT OF THE WORKOUT

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Completing the square SLIDE 1 Revision ? State the quadratic formula to find the roots of the above equation. ? The graph of is a parabola. State the equation of the axis of reflective symmetry of this parabola. SLIDE 2 Quadratic equation Quadratic formula Axis of reflective symmetry This can be seen directly from the quadratic formula. The axis of symmetry lies midway between the two roots, and the formula gives the roots as . SLIDE 3 ? Solve . ? Find the equation of the axis of symmetry of the parabola , the minimum value, and sketch the parabola. SLIDE 4 Axis of symmetry at SLIDE 5 Note. is the Greek letter m, pronounced “mu” as in “music”. ? Expand and collect ? Find the values of the constants . ? Substitute for in to obtain an equation for in the form SLIDE 6 ? ? ? SLIDE 7 Axis of symmetry , minimum point ? State the relation between the axis of reflective symmetry of the parabola and the constants . ? State the minimum point of in terms of the constants . SLIDE 8 Axis of symmetry , minimum point ? The axis of reflective symmetry is . ? The minimum point of is at SLIDE 9 The completed square Any quadratic function may be written in the form This form is called the completed square for the quadratic function. From this form, the axis of reflective symmetry of the parabola defined by is and its minimum or maximum is at . The constant is the scale factor of the quadratic function. If , then the parabola has a minimum. If , then the parabola has a maximum. Because the form makes all this information about the function and curve (parabola) transparent, it is called the standard or canonical form of the quadratic function. SLIDE 10 Finding the completed square form There are two methods for finding the completed square form – an algebraic method that we have already practised, and a method involving direct manipulation. The second method is more efficient, but we begin with the algebraic approach. Algebraic method It is given that . ? By expanding the right-hand side of this equation and equating coefficients, find the completed square form of ? State the axis of symmetry and minimum point of and sketch its parabola. (It is not required to find the roots.) SLIDE 11 because the coefficient of is 1. This simplifies the working. Equating coefficients SLIDE 12 Find the completed square form of and sketch its parabola. Hint. The negative coefficient of the quadratic term indicates that the parabola has a maximum. SLIDE 13 SLIDE 14 Method of direct manipulation The coefficient of the x term here is 5. Half of this number is and the square of this is . Add and subtract simultaneously from the equation. (1, 2) This step is called completing the square because . Tidy up the “back end”. 1. Because we have added and subtracted we have really added 0, so the equation remains true. This is called a plus / minus trick. 2. Do not unsquare the first just after the 5x term, because it is the we want when we complete the square at the next step. The method of direct manipulation is more efficient. SLIDE 15 Find (by direct manipulation) the completed square form of and sketch its parabola. SLIDE 16 SLIDE 17 Find the completed square form of and sketch its parabola. SLIDE 18 SLIDE 19 Find the completed square form of and sketch its parabola. SLIDE 20 SLIDE 21 Find the completed square form of and sketch its parabola. Note. This problem extends the technique by involving fractions. SLIDE 22 SLIDE 23 Find the completed square form of and sketch its parabola. SLIDE 24 SLIDE 25 Find the completed square form of and sketch its parabola. SLIDE 26 SLIDE 27 Find the completed square form of and sketch its parabola. Remark. This graph of this quadratic function does not cross the x-axis. SLIDE 28 SLIDE 29 Real roots The quadratic function has completed square form with minimum . The graph of this function does not cross the x-axis, and the quadratic function does not have roots that are real numbers. By completing the square, we can sketch a quadratic function that has no real roots. We have learnt earlier to sketch quadratic functions by finding their roots. ? Attempt to use the quadratic formula to find the roots of . What problem do you encounter? Why are you unable to find the roots of this quadratic function? SLIDE 30 Using the quadratic formula At this point we appear to arrive at an impasse, or impossible situation, as we encounter a negative square root. The lesson we derive from this situation is that the process of completing the square is more versatile than the process of finding the roots of a quadratic function, as we can sketch the graph whether the function does or does not have real roots. Advanced Mathematicians define and declare a negative root to exist. By this means all quadratic functions can be factorised. This leads to the topic of complex numbers. The study of complex numbers occurs at a higher level. SLIDE 31 Find the completed square form of and sketch its parabola. Real roots This parabola does not cross the x-axis, and the quadratic function does not have roots that are real numbers. SLIDE 32 SLIDE 33 Find the completed square form of and sketch its parabola. SLIDE 34 SLIDE 35 We now extend the method to the case where there is a coefficient in front of the quadratic term. Example Find the completed square form of . Solution The coefficient of the term here is 2 Take this coefficient outside the quadratic and linear terms, but not the constant term. Inside the bracket add and subtract half the coefficient of the linear term. Take the negative square outside the bracket, being careful to multiply by the coefficient outside the bracket. Complete the square. Tidy up the “back end” SLIDE 36 Find the completed square form of and sketch its parabola. SLIDE 37 SLIDE 38 Any quadratic function may be written in the form . The minimum of the graph of y is at . The completed square form of is . The minimum is at . ? What is the effect of the factor on the graph of y? How does affect or change the shape of the parabola? SLIDE 39 In the effect of the scale factor is to change the “steepness” of the parabola. If then the parabola has everywhere (except for the turning point) a steeper gradient than the corresponding parabola where . is “twice as steep” as SLIDE 40 Find the completed square form of and sketch its parabola. SLIDE 41 SLIDE 42 Find the completed square form of and sketch its parabola. Note. The effect of is to “flip” the parabola – it has a maximum rather than a minimum. SLIDE 43 SLIDE 44 Proof of the Quadratic Formula The proof of the quadratic formula proceeds by completing the square. To demonstrate the formula all we follow through the steps of the previous exercises but with the parameters a, b and c in place of their values. By completing the square on c, show that the solutions to the quadratic equation is given by Note. Here we have added the subscripts 1, 2 to because generally there are two solutions to the quadratic equation. The formula is valid even if the expression equates to a negative square root. We will take the proof in steps. The coefficient of the term is a ? …. Take this coefficient outside the quadratic and linear terms, but not the constant term. SLIDE 45 ? …. Inside the bracket add and subtract the square of half the coefficient of the linear term. SLIDE 46 ? …. Take the negative square outside the bracket, being careful to multiply by the coefficient outside the bracket. SLIDE 47 ? …. Complete the square and simplify SLIDE 48 ? …. Tidy up the “back end” SLIDE 49 ? …. Take to the right-hand side. SLIDE 50 ? …. Take the square root of both sides of the equation. There can be positive and negative values. SLIDE 51 ? …. Simplify the right-hand side and bring to the right-hand side. SLIDE 52 Proof of the quadratic formula SLIDE 53 The completed square form of is . Use this information to solve the equation . SLIDE 54 The completed square form of is . Use this information to solve the equation . Solution Reference The coefficient of the term is a Take this coefficient outside the quadratic and linear terms, but not the constant term. Inside the bracket add and subtract half the coefficient of the linear term. Take the negative square outside the bracket, being careful to multiply by the coefficient outside the bracket. Complete the square and simplify Tidy up the “back end” Take to the right-hand side. Take the square root of both sides of the equation. There can be positive and negative values. Simplify the right-hand side and bring to the right-hand side. Reference